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Solve, using the substitution method.

y = 2x + 6
3x – y = 6

Question 4.4. Solve, using the substitution method.

y– 2x = 8
16 + 4x = 2y


Sagot :

y = 2x + 6 ;
y = 3x - 6 ;
2x + 6 = 3x - 6 ;
2x - 3x = - 6 - 6 ;
-x = - 12 ;
x = 12 ;
y = 2*12 + 6 ;
y = 30 ;
The solution is ( 12 , 30 ) ;
y = 2x + 6 ⇒ 2x - y = -6 ⇒ 6x - 3y = -18
3x - y = 6 ⇒ 3x - y = 6   ⇒ 6x - 2y = 18
                                                   -y = -36
                                                    y = 36
                                          2x - 36 = -6
                                               +36  +36
                                                 2x = 30
                                                  2      2
                                                   x = 15
                                             (x, y) = (15, 36)
-----------------------------------------------------------------------------------------------
1y - 2x = 8    ⇒ -2x + 1y = 8   ⇒ 4x - 2y = -16
16 + 4x = 2y ⇒  4x - 2y = -16 ⇒ 4x - 2y = -16
                                                           8x = 0
                                                            8     8 
                                                             x = 0
                                                  4(0) - 2y = -16
                                                      0 - 2y = -16
                                                          -2y = -16
                                                           -2       -2
                                                             y = 8
                                                       (x, y) = (0, 8)
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