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Sagot :
First, take a look at 3 less than twice x. Twice x would be 2x and 3 less than it would become 2x-3.
Next, 2 more than the quantity 3 times x. The quantity of 3 times x is 3x and 2 more than that would be 3x+2.
Now that we have our two equations, we need to multiply them together, which can be shown as (2x-3)(3x+2).
Then, multiply the two equations together using FOIL (multiply the first two terms, then the outside terms, then inside, and lastly, the last two terms): 2x times 3x, 2x times 2, -3x times 3x, and 2 times -3, which equates to 6x^2+4x-9x-6.
Your final answer is 6x^2-5x-6.
Next, 2 more than the quantity 3 times x. The quantity of 3 times x is 3x and 2 more than that would be 3x+2.
Now that we have our two equations, we need to multiply them together, which can be shown as (2x-3)(3x+2).
Then, multiply the two equations together using FOIL (multiply the first two terms, then the outside terms, then inside, and lastly, the last two terms): 2x times 3x, 2x times 2, -3x times 3x, and 2 times -3, which equates to 6x^2+4x-9x-6.
Your final answer is 6x^2-5x-6.
The expression is 6 + 5x - 6x².
What is a quadratic equation?
'A quadratic equation is an algebraic equation of the second degree in x. The quadratic equation in its standard form is ax² + bx + c = 0, where a and b are the coefficients, x is the variable, and c is the constant term.'
According to the given problem,
The expression formed out of he given problem,
= ( 3 - 2x )( 2 + 3x )
= 6 + 9x - 4x - 6x²
= 6 + 5x - 6x²
Hence, we can conclude, the expression is 6 + 5x - 6x².
Learn more about quadratic equations here: https://brainly.com/question/24817658
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