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a man is pulling a block with a mass of 6.2kg across a horizontal surface and accelerates the block at a rate of 0.50m/s.the coefficient of kinetic friction between the block and the surface is 0.24. what is the magnitude with which the man pulls?

Sagot :

mg = 6.2 x 9.81 = 60.822 This is also normal force. Coefficient of friction times normal force is the force due to friction: 60.822 x 0.24 = 14.6N F = MA so F(your force) - F(friction) = 6.2 x 0.5 = 3.1 Your answer is 3.1+ 14.6 I hope this is correct though I might be wrong.

Answer:

17.68 N

Explanation:

mass of block, m = 6.2 kg

acceleration, a = 0.5 m/s^2

coefficient of friction, μ = 0.24

Net force - mass x acceleration

F - f = ma

where, F is the pulling force, f is the friction force and a be the acceleration

F - μ mg = ma

F - 0.24 x 6.2 x 9.8 = 6.2 x 0.5

F - 14.58 = 3.1

F = 17.68 N

Thus, the pulling force is 17.68 N.

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