Westonci.ca is your trusted source for finding answers to all your questions. Ask, explore, and learn with our expert community. Get quick and reliable solutions to your questions from a community of seasoned experts on our user-friendly platform. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.
Sagot :
mg = 6.2 x 9.81 = 60.822
This is also normal force.
Coefficient of friction times normal force is the force due to friction:
60.822 x 0.24 = 14.6N
F = MA so F(your force) - F(friction) = 6.2 x 0.5
= 3.1
Your answer is 3.1+ 14.6
I hope this is correct though I might be wrong.
Answer:
17.68 N
Explanation:
mass of block, m = 6.2 kg
acceleration, a = 0.5 m/s^2
coefficient of friction, μ = 0.24
Net force - mass x acceleration
F - f = ma
where, F is the pulling force, f is the friction force and a be the acceleration
F - μ mg = ma
F - 0.24 x 6.2 x 9.8 = 6.2 x 0.5
F - 14.58 = 3.1
F = 17.68 N
Thus, the pulling force is 17.68 N.
Thank you for your visit. We are dedicated to helping you find the information you need, whenever you need it. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Keep exploring Westonci.ca for more insightful answers to your questions. We're here to help.
