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how do i solve 2x^2+5x+2=9

Sagot :

Panoyin
2x² + 5x + 2 = 9
2x² + 5x + 2 - 9 = 9 - 9
2x² + 5x - 7 = 0
x = -5 +/- √(5² - 4(2)(-7))
                    2(2)
x = -5 +/- √(25 + 56)
                   4
x = -5 +/- √(81)
               4
x = -5 +/- 9
            4
x = -5 + 9      x = -5 - 9
           4                   4
x = 4              x = -14
      4                      4
x = 1              x = -3.5
konrad509
[tex]2x^2+5x+2=9\\ 2x^2+5x-7=0\\ 2x^2-2x+7x-7=0\\ 2x(x-1)+7(x-1)=0\\ (2x+7)(x-1)=0\\ x=-\dfrac{7}{2} \vee x=1[/tex]
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