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Sagot :
-6y + 2x = 18
Subtract 2x to both sides:
-6y = -2x + 18
Divide -6 to both sides:
y = -2/-6x - 3
Simplify:
y = 1/3x - 3
Now it's in the form of y = mx + b, where 'm' is the slope.
So the slope here is 1/3.
Subtract 2x to both sides:
-6y = -2x + 18
Divide -6 to both sides:
y = -2/-6x - 3
Simplify:
y = 1/3x - 3
Now it's in the form of y = mx + b, where 'm' is the slope.
So the slope here is 1/3.
First of all, I would like to thank Cosmos for deleting my incorrect answer. (applause)
Now, we will proceed to our main program.
Manipulate -6y + 2x = 18 into the y = mx + b form.
Subtract 2x from both sides
-6y = -2x + 18
Divide both sides by -6
[tex]y = \frac{-2}{-6}x + \frac{18}{-6} [/tex]
Simplify
[tex]y = \frac{1}{3} x - 3[/tex]
The slope will be the coefficient of x.
[tex]The\ slope\ is\ \frac{1}{3} \ .[/tex]
Now, we will proceed to our main program.
Manipulate -6y + 2x = 18 into the y = mx + b form.
Subtract 2x from both sides
-6y = -2x + 18
Divide both sides by -6
[tex]y = \frac{-2}{-6}x + \frac{18}{-6} [/tex]
Simplify
[tex]y = \frac{1}{3} x - 3[/tex]
The slope will be the coefficient of x.
[tex]The\ slope\ is\ \frac{1}{3} \ .[/tex]
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