Answered

Find the best answers to your questions at Westonci.ca, where experts and enthusiasts provide accurate, reliable information. Get expert answers to your questions quickly and accurately from our dedicated community of professionals. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.

how do I find when two quadratic functions are at the same point by using the substitution method. here are the two equations:
y=-16x^2+150x+5 and y=54x+5 where x is measured in seconds


Sagot :

y = -16x² + 150x + 5
y = 54x + 5
  54x + 5 = -16x² + 150x + 5
- 54x                    -   54x       
            5 = -16x² + 96x + 5
         - 5                         - 5
            0 = -16x² + 96x
       16x² = -16x² + 16x² + 96
       16x² = 96
        16      16
           x² = 6
           x =+/-√(6)
y = -16(√(6)²) + 150√(6) + 5
y = -16(6) + 150√(6) + 5
y = -96 + 5 + 150√(6)
y = -91 + 150√(6)
(x, y) = (√(6), -91 + 150√(6))
or
y = -16(-√(6)²) + 150(-√(6)) + 5
y = -16(-6) + 150(-√(6)) + 5
y = 96 + 5  +150(-√(6))
y = 101 + 150(-√(6))
(x, y) = (-√(6), 101 + 150(-√(-6)))