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Solve using quadratic formula x squared -2x-8=0

Sagot :

TSO
[tex]x= \frac{-b\pm \sqrt{b^2-4ac} }{2a} [/tex] for the equation [tex]ax^2+bx+c[/tex]

Your question is [tex]x^2-2x-8=0[/tex]

So [tex]a=1 \\b=-2\\c=-8[/tex]

So plug in your numbers:
[tex]x= \frac{-(-2)\pm \sqrt{(-2)^2-4(1)(-8)} }{2(1)}[/tex]

Simplify:
[tex]x= \frac{2\pm \sqrt{4-(-32)} }{2}[/tex]

Simplify a little more:
[tex] \frac{2\pm6}{2} [/tex]

So our answer is
[tex]x= \frac{2+ 6 }{2} = 4\\x= \frac{2- 6 }{2}=-2[/tex]

So [tex]x=4, x=-2[/tex]
Panoyin
x² - 2x - 8 = 0
x = -(-2) +/- √((-2)² - 4(1)(-8))
                      2(1)
x = 2 +/- √(4 + 32)
                 2
x = 2 +/- √(36)
              2
x = 2 +/- 6
           2
x = 1 +/- 3
x = 1 + 3      x = 1 - 3
x = 4            x = -2
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