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Intersection of Two Lines

x+y=3
2x+y=5

Solve by the Elimination Method

Sagot :

naǫ
[tex]x+y=3 \ \ \ |\times (-1) \\ 2x+y=5 \\ \\ -x-y=-3 \\ \underline{2x+y=5 \ \ \ \ } \\ 2x-x=5-3 \\ x=2 \\ \\ x+y=3 \\ 2+y=3 \\ y=3-2 \\ y=1 \\ \\ \hbox{the point of intersection - } (x,y)=(2,1) [/tex]
Panoyin
1x + 1y = 3 ⇒ 2x + 2y = 6
2x + 1y = 5 ⇒ 2x + 1y = 5
                                 y = 1
                         2x + 1 = 5
                               - 1 - 1
                               2x = 4
                                2     2
                                 x = 2
                           (x, y) = (2, 1)
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