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Sagot :
A direct proportion is any equation where y = mx+b. (i.e., a linear equation)
Each side of 3y = 1/2x can be divided by 3 to get y = 1/6x, satisfying the condition of y = mx+b. (b=0)
In this case, the constant of proportionality would be 1/6.
Each side of 3y = 1/2x can be divided by 3 to get y = 1/6x, satisfying the condition of y = mx+b. (b=0)
In this case, the constant of proportionality would be 1/6.
Yes, there is.
Just divide 3 to both sides:
y = (1/2 / 3)x
Find the reciprocal of 3 and multiply:
y = (1/2 * 1/3)x
Multiply the numerators and denominators together:
y = 1/6x
So the constant of proportionality is 1/6.
Just divide 3 to both sides:
y = (1/2 / 3)x
Find the reciprocal of 3 and multiply:
y = (1/2 * 1/3)x
Multiply the numerators and denominators together:
y = 1/6x
So the constant of proportionality is 1/6.
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