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3x^2+13x+10=0 please help

3x213x100 Please Help class=

Sagot :

I will use the quadratic equation to solve this:
x= -b +(or minus, both) √b² + 4ac
     --------------------------------------------
                          2a
So, your numbers would be:   a = 3
                                           b = 13 
                                           c = 10
Then, solve: x = -13 +(or minus, both) √169 + 120
                        --------------------------------------------------
                                               6
                       = -13 +(or minus, both) 17
                         ------------------------------------
                                        6
So, first do the plus: -13 + 17
                              --------------
                                    6
                             = 2/3
Then do the minus:    -13-17
                                ------------
                                    6
                              = 5

Your answer is: 2/3 and 5
( These problems always have two answers)

The answer and explanation is in the attachment.
View image ajluv3161
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