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how many moles of N2 are in a flask with a volume of 250ml at a pressure of 300.0 KPa and a temp of 300.0 K

Sagot :

mhairforce32
It solve by PV=nRT 300×10^3×250×10^-6=n×8×300 And so on

Answer : The number of moles of [tex]N_2[/tex] are, 0.03 mole

Solution :

Using ideal gas equation,

[tex]PV=nRT[/tex]

where,

P = pressure of the gas = 300 kpa = 2.96 atm

conversion : 1 atm = 101.325 kpa

V = volume of the gas = 250 ml  = 0.250 L

conversion : 1 L = 1000 ml

T = temperature of the gas = 300 K

R = universal gas constant = 0.0821 Latm/moleK

n = number of moles of gas

Now put all the given values in the above formula, we get the number of moles of gas.

[tex]2.96atm\times 0.250L=n\times 0.0821Latm/moleK\times 300K[/tex]

[tex]n=0.03mole[/tex]

Therefore, the number of moles of [tex]N_2[/tex] are, 0.03 mole

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