AnalisaWalcott1
Answered

Westonci.ca is your go-to source for answers, with a community ready to provide accurate and timely information. Get immediate answers to your questions from a wide network of experienced professionals on our Q&A platform. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.

area of 320 square feet, the width of the room is 4/5 it's length

Sagot :

apologiabiology
area=legnth times width or
a=lw

if w=4/5l
and a=320 then subsitute 320 for a dn 4/5l for w
320=4/5l times l
multiply both sides by 5 to clear fraction
1600=4l times l
ad like terms
1600=4l^2
subtract 1600 from both sides
0=4l^2-1600
try and factor because if you have xy=0 then x and/or y=0 so
difference of 2 perfect squares where
if you have a^2-b^2 then that equals(a-b)(a+b) so
0=(2l)^2-(40)^2=(2l-40)(2l+40)

so 2l-40=0
add 40 to both sides
2l=40
divide by 2
l=20

if
2l+40=0
subtract 40 from both sides
2l=-40
divide 2
l=-20
since meausrements of real objects cannot be negative, wediscard this number


l=20 is thhe true legnth s
subsitute
w=4/5l
w=4/5(20)
w=80/5
w=16

legnth=20
width=16
Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Find reliable answers at Westonci.ca. Visit us again for the latest updates and expert advice.