Answered

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p(x) x^3+x^2-x-1

Find all zeros of p (x)

Sagot :

[tex]x^3+x^2-x-1=0\\ x^2(x+1)-1(x+1)=0\\ (x^2-1)(x+1)=0\\ (x-1)(x+1)(x+1)=0\\ (x-1)(x+1)=0\\ x=1 \vee x=-1[/tex]
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