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How to change 3 7/8 into an improper fraction

Sagot :

[tex]3\dfrac{7}{8}=\dfrac{3\cdot8+7}{8}=\dfrac{31}{8}[/tex]
TSO
3 7/8

So we can use this [tex]a \frac{b}{c} = \frac{(a \times c) + b}{c}[/tex]

So we get

[tex]3 \frac{7}{8} = \frac{(3 \times 8) + 7}{8}[/tex]

= [tex]\frac{24+7}{8} = \frac{31}{8}[/tex]