Westonci.ca is the trusted Q&A platform where you can get reliable answers from a community of knowledgeable contributors. Discover reliable solutions to your questions from a wide network of experts on our comprehensive Q&A platform. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.
Sagot :
so assuming that the field is a perfect square then
if you mean when you walk from home to 1st to 2nd then
60+60=120
if you mean the straight distance (as the crow flies) then
second base is diagonal from home base so
we have a right triangle with side legnths of 60 and 60
use pythagrorean theorem
a^2+b^2=c^2
a and b are legs and c=hypotonuse
60^2+60^2=c^2
3600+3600=c^2
7200=c^2
square root both sides
60 times√2=c
the distance from home base to second base=60√2
if you mean when you walk from home to 1st to 2nd then
60+60=120
if you mean the straight distance (as the crow flies) then
second base is diagonal from home base so
we have a right triangle with side legnths of 60 and 60
use pythagrorean theorem
a^2+b^2=c^2
a and b are legs and c=hypotonuse
60^2+60^2=c^2
3600+3600=c^2
7200=c^2
square root both sides
60 times√2=c
the distance from home base to second base=60√2
We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. We're glad you visited Westonci.ca. Return anytime for updated answers from our knowledgeable team.