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Sagot :
Let the number of 3-hour days be x while the number of 4-hour days be y
The number of 3-hour and 4-hour days add up to 14 (x+y=14)
Also 3 hours times number of 3-hour days plus 4-hours times number of 4-hour days add up tp 48 (3x+4y=48)
That gives us two simultaneous equations: x+y=14
3x+4y=48
x=14-y
Putting that x equation into the second equation 3(14-y)+4y=48
42-3y+4y=48
4y-3y=48-42
y=6
x+y=14
x=14-6
x=8
Elizabeth worked 8 3-hour days and 6 4-hour days
The number of 3-hour and 4-hour days add up to 14 (x+y=14)
Also 3 hours times number of 3-hour days plus 4-hours times number of 4-hour days add up tp 48 (3x+4y=48)
That gives us two simultaneous equations: x+y=14
3x+4y=48
x=14-y
Putting that x equation into the second equation 3(14-y)+4y=48
42-3y+4y=48
4y-3y=48-42
y=6
x+y=14
x=14-6
x=8
Elizabeth worked 8 3-hour days and 6 4-hour days
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