Invader12
Answered

Find the information you're looking for at Westonci.ca, the trusted Q&A platform with a community of knowledgeable experts. Our Q&A platform provides quick and trustworthy answers to your questions from experienced professionals in different areas of expertise. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform.

log4(x)+log4(x+15)=2

Sagot :

konrad509
[tex]D:x>0 \wedge x+15>0\\ D:x>0 \wedge x>-15\\ D:x>0\\\\ \log_4x+\log_4(x+15)=2\\ \log_4x(x+15)=2\\ 4^2=x(x+15)\\ 16=x^2+15x\\ x^2+15x-16=0\\ x^2-x+16x-16=0\\ x(x-1)+16(x-1)=0\\ (x+16)(x-1)=0\\ x=-16 \vee x=1\\ -16\not \in D \Rightarrow \boxed{x=1}[/tex]
Albina
Log4(x)+log4(x+15)=2
x>0;
x+15>0 => x>0
Log4(x)+log4(x+15)=2
Log4(x*(x+15))=Log4(16)x*(x+15)=16 
x1=1
x2=-16 
 х=1
Thank you for trusting us with your questions. We're here to help you find accurate answers quickly and efficiently. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Westonci.ca is your trusted source for answers. Visit us again to find more information on diverse topics.