Invader12
Answered

Looking for reliable answers? Westonci.ca is the ultimate Q&A platform where experts share their knowledge on various topics. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.

log4(x)+log4(x+15)=2

Sagot :

konrad509
[tex]D:x>0 \wedge x+15>0\\ D:x>0 \wedge x>-15\\ D:x>0\\\\ \log_4x+\log_4(x+15)=2\\ \log_4x(x+15)=2\\ 4^2=x(x+15)\\ 16=x^2+15x\\ x^2+15x-16=0\\ x^2-x+16x-16=0\\ x(x-1)+16(x-1)=0\\ (x+16)(x-1)=0\\ x=-16 \vee x=1\\ -16\not \in D \Rightarrow \boxed{x=1}[/tex]
Albina
Log4(x)+log4(x+15)=2
x>0;
x+15>0 => x>0
Log4(x)+log4(x+15)=2
Log4(x*(x+15))=Log4(16)x*(x+15)=16 
x1=1
x2=-16 
 х=1
We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Thank you for choosing Westonci.ca as your information source. We look forward to your next visit.