Answered

Westonci.ca makes finding answers easy, with a community of experts ready to provide you with the information you seek. Get immediate and reliable solutions to your questions from a community of experienced experts on our Q&A platform. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.

write the expression(4x-2)·6(2x+7) in the standard form of a quadratic expression,
ax²+bx+c

Sagot :

BumblebeeBVB
[tex](4x-2)*6(2x+7)=(4x-2)*(12x+42)[/tex] I can do this because of distribution, which I will use again in the following: [tex](4x-2)*(12x+42)=48x^2-24x+168x-84=48x^2+144-84[/tex]

This is the answer.
Panoyin
(4x - 2)(6(2x + 7)) = 0
(4x - 2)(6(2x) + 6(7)) = 0
(4x - 2)(12x + 42) = 0
48x² + 168x - 24x - 84 = 0
48x² + 144x - 84 = 0
x = -144 +/- √(144² - 4(48)(-84))
                        2(48)
x = -144 +/- √(20,736 - 16,128)
                           96
x = -144 +/- √(4,608)
                  96
x = -144 +/- 67.88
                96
x = -1.5 +/- 0.707083
x = -1.5 + 0.707083      x = -1.5 - 0.707083
x = -0.792917               x = -2.207083
We appreciate your visit. Hopefully, the answers you found were beneficial. Don't hesitate to come back for more information. We appreciate your time. Please come back anytime for the latest information and answers to your questions. Thank you for using Westonci.ca. Come back for more in-depth answers to all your queries.