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give the function f (x) =9x+7, find its inverse

Sagot :

konrad509
[tex]f(x)=9x+7\\ y=9x+7\\ 9x=y-7\\ x=\dfrac{1}{9}y-\dfrac{7}{9}\\ f^{-1}(x)=\dfrac{1}{9}x-\dfrac{7}{9}\\[/tex]

Applying it's definition, the inverse of the function f(x) = 9x + 7 is given by:

[tex]f^{-1}(x) = \frac{x - 7}{9}[/tex]

How to find the inverse of a function?

Suppose we have a function y = f(x). To find the inverse function, we exchange x and y in the original function, then isolate f.

In this problem, the function is:

y = 9x + 7

Exchanging:

x = 9y + 7

Isolating y:

9y = x - 7

[tex]y = \frac{x - 7}{9}[/tex]

[tex]f^{-1}(x) = \frac{x - 7}{9}[/tex]

More can be learned about inverse functions at https://brainly.com/question/8824268

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