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Sagot :
We can set up an inequality.
[tex]119.75+2.25x\le~500[/tex]
Subtract 119.75 to both sides:
[tex]2.25x\le~380.25[/tex]
Divide 2.25 to both sides:
[tex]x\le~169[/tex]
So the maximum number of pastries that can be baked each day is 169.
[tex]119.75+2.25x\le~500[/tex]
Subtract 119.75 to both sides:
[tex]2.25x\le~380.25[/tex]
Divide 2.25 to both sides:
[tex]x\le~169[/tex]
So the maximum number of pastries that can be baked each day is 169.
Answer:
The answer is C, 119.75+2.25p [tex]\leq[/tex] 169
Step-by-step explanation:
I did this for homework
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