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Solve 4r^2 – 5 = 59.


(Points : 1)
{± 3}
{± 4}
{± 5}
{±6}


Sagot :

[tex]4r^{2} =64 r^{2} =16 r= \sqrt{16} = ±4

4r² - 5 = 59
     + 5  + 5
     4r² = 64
      4       4
       r² = 16
       r = +4

The answer to the problem is equal to +4