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Sagot :
9 pieces of rope form an 8 yard long rope
Divide.
8/9 yards of rope.
8/9 is approximately 0.89.
So 8/9 yards of rope or 0.89 yards of rope.
Divide.
8/9 yards of rope.
8/9 is approximately 0.89.
So 8/9 yards of rope or 0.89 yards of rope.
ANSWERS
Each rope has a length of 8/9 yards, or [tex]0.\overline{8} [/tex] yards (repeating digit is 8).
EXPLANATION
Division can be used to solve this problem.
In general, the equation "a/b = c" models the following situation: If you have something that is a units long and you divide it into b equal parts, then each equal part will be c units long.
We have a rope that is 8 yards long and we need 9 equal pieces.
Divide 8 yards by 9 to get the length of each piece.
[tex]\begin{aligned} {}^\text{length of}_\text{each piece} &= \dfrac{8\text{ yard}}{\text{9 piece} } \\ &= 8/9 \text{ yards per piece} \\ &= 0.\overline{8} \text{ yards per piece} \end{aligned}[/tex]
Each piece is 8/9th of a yard or [tex]0.\overline{8} [/tex] yards long.
We can confirm this by adding the lengths of the nine equal pieces of rope back up to get the original length of the rope:
[tex]\begin{aligned} \underbrace{\frac{8}{9} + \frac{8}{9} + \frac{8}{9} +\frac{8}{9} +\frac{8}{9} +\frac{8}{9} +\frac{8}{9} +\frac{8}{9} +\frac{8}{9}}_{\text{9 pieces, each of them 8/9th of a yard long}} &= 9 \cdot \left(\frac{8}{9} \right) \\ &= 8 \end{aligned}[/tex]
Each rope has a length of 8/9 yards, or [tex]0.\overline{8} [/tex] yards (repeating digit is 8).
EXPLANATION
Division can be used to solve this problem.
In general, the equation "a/b = c" models the following situation: If you have something that is a units long and you divide it into b equal parts, then each equal part will be c units long.
We have a rope that is 8 yards long and we need 9 equal pieces.
Divide 8 yards by 9 to get the length of each piece.
[tex]\begin{aligned} {}^\text{length of}_\text{each piece} &= \dfrac{8\text{ yard}}{\text{9 piece} } \\ &= 8/9 \text{ yards per piece} \\ &= 0.\overline{8} \text{ yards per piece} \end{aligned}[/tex]
Each piece is 8/9th of a yard or [tex]0.\overline{8} [/tex] yards long.
We can confirm this by adding the lengths of the nine equal pieces of rope back up to get the original length of the rope:
[tex]\begin{aligned} \underbrace{\frac{8}{9} + \frac{8}{9} + \frac{8}{9} +\frac{8}{9} +\frac{8}{9} +\frac{8}{9} +\frac{8}{9} +\frac{8}{9} +\frac{8}{9}}_{\text{9 pieces, each of them 8/9th of a yard long}} &= 9 \cdot \left(\frac{8}{9} \right) \\ &= 8 \end{aligned}[/tex]
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