Answered

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2x-8/x^2
what is the range of this function ?

Sagot :

Hippalectryon
The function is continuous for [tex]x>0[/tex]. It goes to [tex]-\infty[/tex] when [tex]x\to0[/tex] and it goes to [tex]+\infty[/tex] when [tex]x\to+\infty[/tex] hence its range is [tex]\Bbb{R}=(-\infty,+\infty)[/tex]
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