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A 14-foot ladder is set up 4 feet from the base of the building. How far up the building does the ladder reach?

Sagot :

This problem creates a right Triangle the building is one side and the 4ft is the other side the ladder is the hypotenuse apply the Pythagorean Theorem'a^2 + b^2= c^2 4^2 + b^2 = 14^2 16+ b^2= 195 b^2= 180 b= square root of 180 b= 6 square root of 5 or 13.42

The distance between the building and the top of the ladder is about 13.42 feet.

Important information:

  • Size of ladder = 14 foot
  • Distance between building and base of ladder = 4 feet

We need to find the distance between the building and the top of the ladder.

Pythagoras Theorem:

Let [tex]x[/tex] be the distance between the building and the top of the ladder. Then, using the Pythagoras theorem, we get

[tex]x^2+(4)^2=(14)^2[/tex]

[tex]x^2=196-16[/tex]

[tex]x=\sqrt{180}[/tex]

[tex]x\approx 13.42[/tex]

Therefore, the distance between the building and the top of the ladder is about 13.42 feet.

Find out more about 'Pythagoras Theorem' here:

https://brainly.com/question/2415994

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