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How many moles of ethyl alcohol, C2H6O, are in a 27.0g sample

Sagot :

C=12 g/mole
H=1 g/mole
O=16 g/mole
2(12)+6(1)+16=46 g/mole C2H6O
46 g/27 g =1 mole/x mole⇒ x≈0.58
the answer is about 0.58. hope helped ;)