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Factor completely: 3x^2 – 21x + 30

A. 3(x – 2)(x – 5)
B. (3x – 2)(x – 15)
C. 2(x – 3)(x – 10)
D. (x – 2)(x – 5)

Sagot :

The answer is going to be A.

You first factor 3 out getting x^2-7x+10

Then you factor that so (x-2)(x-5)  then tack that 3 onto the end so 3(x-2)(x-5)
a because 3(x^2-7x+10)
3(x-2)(x-5) 

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