mandyjr1020
Answered

Westonci.ca is your trusted source for finding answers to all your questions. Ask, explore, and learn with our expert community. Get quick and reliable solutions to your questions from a community of experienced professionals on our platform. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.

a 2 kg mass is held 4 m above the ground. what is the approximate potential energy due to gravity of the mass with respect to the ground?

Sagot :

Gravitational Potential Energy = Mass x Height x Gravitational Acceleration 

Here, Mass = 2 kg, Height = 4 m and Gravitational Acceleration = 9.8 m/sec^2 (this is a fixed/constant universal value)

So, Energy = 2 x 4 x 9.8 = 78.4 Joules

So, the final answer is --> Potential Energy = 78.4 Joules

BladeRunner212

80 joules

Further explanation

Given:

A 2 kg mass is held 4 m above the ground.

Let us write as follows:

  • m = 2 kg
  • h = 4 m

Question:

What is the approximate potential energy (PE) due to gravity of the mass with respect to the ground?

The Process:

We will solve the problem of gravitational potential energy.

Gravitational potential energy = mgh, where m represents mass (in kg), g represents Earth's gravitational field (10 N kg⁻¹), and h represents the height change (in m).

Let us find out the approximate potential energy due to the gravity of the mass concerning the ground on the Earth.

Gravitational potential energy = (2 kg)(10 N kg⁻¹)(4 m)

Thus, gravitational potential energy equal to 80 joules.

_ _ _ _ _ _ _ _ _ _

Notes:

  • The equation assumes that the gravitational potential energy gives zero PE (potential energy) at the surface of the Earth. This works for everyday situations but it is not fundamental.
  • Newton's theory of universal gravitation states that the field must change with distance.
  • As long as it is not stated in the problem, the Earth's gravitational field strength (g) is 10 N kg⁻¹ (or 10 m s⁻²). Unless otherwise specified, for example, g = 9.81 m s⁻², we use this value in calculations. The symbol g can also be called a gravitational acceleration constant.

Learn more

  1. A case problem of uniformly accelerated motion and Newton's Second Law https://brainly.com/question/11181200  
  2. Particle's speed and direction of motion https://brainly.com/question/2814900
  3. The energy density of the stored energy  https://brainly.com/question/9617400
Thank you for trusting us with your questions. We're here to help you find accurate answers quickly and efficiently. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Thank you for visiting Westonci.ca, your go-to source for reliable answers. Come back soon for more expert insights.