Westonci.ca is the Q&A platform that connects you with experts who provide accurate and detailed answers. Get immediate and reliable answers to your questions from a community of experienced experts on our platform. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.
Sagot :
Gravitational Potential Energy = Mass x Height x Gravitational Acceleration
Here, Mass = 2 kg, Height = 4 m and Gravitational Acceleration = 9.8 m/sec^2 (this is a fixed/constant universal value)
So, Energy = 2 x 4 x 9.8 = 78.4 Joules
So, the final answer is --> Potential Energy = 78.4 Joules
Here, Mass = 2 kg, Height = 4 m and Gravitational Acceleration = 9.8 m/sec^2 (this is a fixed/constant universal value)
So, Energy = 2 x 4 x 9.8 = 78.4 Joules
So, the final answer is --> Potential Energy = 78.4 Joules
80 joules
Further explanation
Given:
A 2 kg mass is held 4 m above the ground.
Let us write as follows:
- m = 2 kg
- h = 4 m
Question:
What is the approximate potential energy (PE) due to gravity of the mass with respect to the ground?
The Process:
We will solve the problem of gravitational potential energy.
Gravitational potential energy = mgh, where m represents mass (in kg), g represents Earth's gravitational field (10 N kg⁻¹), and h represents the height change (in m).
Let us find out the approximate potential energy due to the gravity of the mass concerning the ground on the Earth.
Gravitational potential energy = (2 kg)(10 N kg⁻¹)(4 m)
Thus, gravitational potential energy equal to 80 joules.
_ _ _ _ _ _ _ _ _ _
Notes:
- The equation assumes that the gravitational potential energy gives zero PE (potential energy) at the surface of the Earth. This works for everyday situations but it is not fundamental.
- Newton's theory of universal gravitation states that the field must change with distance.
- As long as it is not stated in the problem, the Earth's gravitational field strength (g) is 10 N kg⁻¹ (or 10 m s⁻²). Unless otherwise specified, for example, g = 9.81 m s⁻², we use this value in calculations. The symbol g can also be called a gravitational acceleration constant.
Learn more
- A case problem of uniformly accelerated motion and Newton's Second Law https://brainly.com/question/11181200
- Particle's speed and direction of motion https://brainly.com/question/2814900
- The energy density of the stored energy https://brainly.com/question/9617400
Thank you for your visit. We are dedicated to helping you find the information you need, whenever you need it. We appreciate your time. Please come back anytime for the latest information and answers to your questions. Get the answers you need at Westonci.ca. Stay informed with our latest expert advice.