Answered

Westonci.ca offers fast, accurate answers to your questions. Join our community and get the insights you need now. Experience the convenience of getting reliable answers to your questions from a vast network of knowledgeable experts. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.

Determine the coordinates of the vertex and horizontal intercepts of the parabola. (If an answer does not exist, enter DNE.)


f(x) = −7(x + 12)2 + 14
I cant figure out the horizontal intercepts.

Sagot :

belcatya
f(x) = −7(x + 12)² + 14
 the coordinates of the vertex are (-12;14)
  f(x)=-7(x²+24x-144)+14
f(x)=-7x²-168x+1008+14
f(x)=-7x²-168x+1022=0
7x²+168x-1022=0
x=[tex] \frac{-168+- \sqrt{ 168^{2} +4*7*1022} }{14} [/tex]=[tex] \frac{-168+- \sqrt{56840} }{14}[/tex]=[tex] \frac{-168+-14 \sqrt{290} }{14} [/tex]=-12+-√290
x₁=-12-√290
x₂=-12+√290
Answer: the coordinates of the vertex are (-12;14),
horizontal intercepts are x₁=-12-√290, x₂=-12+√290




Thanks for stopping by. We are committed to providing the best answers for all your questions. See you again soon. We hope this was helpful. Please come back whenever you need more information or answers to your queries. We're here to help at Westonci.ca. Keep visiting for the best answers to your questions.