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Solve the equation 7x^2-8x=-1

Sagot :

belcatya
7x²-8x=-1
7x²-8x+1=0
on theorem Vieta if 7-8+1=0 ⇒x₁=1
(7x²-7x)-(x-1)=0
7x(x-1)-(x-1)=0
(x-1)(7x-1)=0
x₂=1/7
Answer: x₁=1  x₂=1/7
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