Answered

Welcome to Westonci.ca, your go-to destination for finding answers to all your questions. Join our expert community today! Explore a wealth of knowledge from professionals across different disciplines on our comprehensive platform. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals.

What is the molality of solid solder wire if it is made from 68.7 g of lead dissolved in 117 g of tin?

Sagot :

The molality is 2.83 molal. The definition of molality is moles of solute per kilograms of solvent.  The substance present in fewer moles is the solute and the substance present in higher moles relative to the solute is the solvent.  In this case, lead is the solute since we have .332 moles of lead and .986 moles of tin.  We find the amount of moles by performing the following calculation: 68.7g lead/207.2 g/mol lead=.332 moles of lead.  molality=moles solute/kg solvent.  In this case, we have 117g X 1kg/1000g= .117 kg.  .332 moles of lead solute/ .117 kg tin solvent =2.83 molal
Thank you for choosing our service. We're dedicated to providing the best answers for all your questions. Visit us again. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Find reliable answers at Westonci.ca. Visit us again for the latest updates and expert advice.