Conqueror
Answered

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(2x^3 + 4x^2 + 15x - 8) / (x - 3)

Use long division

Sagot :

iGreen
I put it all in the attachment.
View image iGreen
[tex]\begin{array}{lll}(2x^3 + 4x^2 +15x-8):(x-3) = 2x^2+10x +45\\ \underline{-2x^3 + 6x^2} & & \\\qquad\ \ 10x^2+15x-8 & & \\\qquad \ \ \underline{-10x^2+30x} & &\\ \qquad \qquad \qquad 45x-8 & & \\ \qquad \qquad \quad \underline{-45x + 135} & & \\ \qquad \qquad \qquad R=127& & \\\end{array}\\\\(2x^3+4x^2+15x-8):(x-3)=2x^2+10x+45+\frac{127}{x-3}\\\\[/tex]
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