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Write a number in which the digit 8 is ten times the value then the digit in 4.381.

Sagot :

One possible answer is:

4.801

Explanation:

In the number 4.381, the digit 8 is in the hundredths place. That makes its value 8/100.

We want a value 10 times this amount; 10*(8/100) = (10/1)*(8/100) = 80/100 = 8/10. This is read as "eight tenths"; this means we want an 8 in the tenths place.

4.801 has an 8 in the tenths place, so it works.

The number where the digit 8 is ten times the value then the digit in 4.381 is 4.801.

Given that,

  • The digit 8 is ten times the value than the digit in 4.381.
  • We need to find the digit.

Based on the above information, the calculation is as follows:

  • Since the number is 4.381.
  • So here 8 should be in the hundred place. So it make the value of 8 by 100.
  • Now here we want the value 10 times.

So,

[tex]= 10\times (8\div 100) \\\\= (10\div 1)\times (8\div 100) \\\\= 80\div 100 \\\\= 8\div 10[/tex]

It is eight tenths that means here we want 8 in the tenth place.

So, 4.801 should be 8 in the tenth place.

Therefore we can conclude that the number where the digit 8 is ten times the value then the digit in 4.381 is 4.801.

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