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Sagot :
This is a classic example of a right angled triangle where the ladder is the hypotenuse and the wall and the base of the wall are the other 2 sides of the triangle.
Since it is a right angled triangle, Pythagorean theorem will be applied to it.
So, we use the formula -
hypotenuse^2 = side1^2 + side2^2
Here, hypotenuse (ladder) = 5 feet, side1 (wall) = 4 feet, side2 (base of the wall) = unknown.
So, we have, 5^2 = 4 ^2 + side2^2
==> side2^2 = 5^2 - 4^2
==> side2^2 = 25 - 16
==> side2^2 = 9
==> side2 = square root (9)
==> side2 = 3
So, the final answer is --> the bottom of the ladder is 3 foot away from the base of the wall.
Since it is a right angled triangle, Pythagorean theorem will be applied to it.
So, we use the formula -
hypotenuse^2 = side1^2 + side2^2
Here, hypotenuse (ladder) = 5 feet, side1 (wall) = 4 feet, side2 (base of the wall) = unknown.
So, we have, 5^2 = 4 ^2 + side2^2
==> side2^2 = 5^2 - 4^2
==> side2^2 = 25 - 16
==> side2^2 = 9
==> side2 = square root (9)
==> side2 = 3
So, the final answer is --> the bottom of the ladder is 3 foot away from the base of the wall.
A right angled triangle is formed here.
By Pythagoras theorem,
H² = B² + L²
where L is the altitude (wall), B is the base (ground) and H is the hypotenuse (ladder).
⇒ 5² = B² + 4²
⇒ 25 = B² + 16
⇒ B² = 25 - 16 = 9
⇒ B = 3
The bottom of the ladder must be 3 feet away from the base of the wall.
By Pythagoras theorem,
H² = B² + L²
where L is the altitude (wall), B is the base (ground) and H is the hypotenuse (ladder).
⇒ 5² = B² + 4²
⇒ 25 = B² + 16
⇒ B² = 25 - 16 = 9
⇒ B = 3
The bottom of the ladder must be 3 feet away from the base of the wall.
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