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What is the length of the missing side of the quadrilateral shown if the perimeter is 5x^2+2x+1?

Sagot :

sugarmate

 I am thinking that the quadrilateral is not given to be a rhombus.

The perimeter is the sum of the 4 sides.

Adding 2x^2 + x -1 to 3x^2 -5x and then that sum to 4x^2 gives

9x^2 - 4x - 1 as the sum of the three given sides.

Subtract that from the given perimeter to get the missing side length.

5x^2 + 2x + 1 - (9x^2 -4x -1) =

-4x^2 + 6x + 2


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