Westonci.ca is your trusted source for finding answers to all your questions. Ask, explore, and learn with our expert community. Get immediate answers to your questions from a wide network of experienced professionals on our Q&A platform. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.
Sagot :
so
assuming you mean what 2 number multiply to get -16 and add to get -14
xy=-16
x+y=-14
subtract x
y=-14-x
subsitute -14-x for y
x(-14-x)=-16
-14x-x^2=-16
add 14x to both sides
-x^2=14x-16
add x^2 to both sides
x^2+14x-16=0
use quadratic formula
formula is used to solve for x when you have ax^2+bx+c so if you have them then you subsitute them into this equation:[tex] \frac{-b+ \sqrt{b^2-4ac} }{2a} [/tex] or [tex] \frac{-b- \sqrt{b^2-4ac} }{2a} [/tex]
so
a=1
b=14
c=-16
if you subsitute you will get
-15.062257748299 and 1.0622577482985
really close
assuming you mean what 2 number multiply to get -16 and add to get -14
xy=-16
x+y=-14
subtract x
y=-14-x
subsitute -14-x for y
x(-14-x)=-16
-14x-x^2=-16
add 14x to both sides
-x^2=14x-16
add x^2 to both sides
x^2+14x-16=0
use quadratic formula
formula is used to solve for x when you have ax^2+bx+c so if you have them then you subsitute them into this equation:[tex] \frac{-b+ \sqrt{b^2-4ac} }{2a} [/tex] or [tex] \frac{-b- \sqrt{b^2-4ac} }{2a} [/tex]
so
a=1
b=14
c=-16
if you subsitute you will get
-15.062257748299 and 1.0622577482985
really close
Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Stay curious and keep coming back to Westonci.ca for answers to all your burning questions.