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If sin α = 12/13 , and cosα = 5/13 , then tanα =?
It would be great if you could add a few words of explanation


Sagot :

If you draw a right angles triangle you can fill in the values. So since sinx= opposite/hypotenuse then the hypotenuse of the triangle is 13. And the side opposite the angle a is 12. Since cosx= adjacent/ hypotenuse, the adjacent side is 5.
Tanx=opposite/adjacent and therefore tana= 12/5
[tex]sin\alpha=\frac{12}{13}\\\\cos\alpha=\frac{5}{13}\\\\tan\alpha=\frac{sin\alpha}{cos\alpha}\\\\tan\alpha=\frac{12}{13}:\frac{5}{13}=\frac{12}{13}\cdot\frac{13}{5}=\frac{12}{5}=2\frac{2}{5}=2.4[/tex]