Welcome to Westonci.ca, your ultimate destination for finding answers to a wide range of questions from experts. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.
Sagot :
Here's the formula for exponential decay:
[tex]A = p(1-k)^t[/tex]
(where A = new amount, p = principal (starting) amount, k = rate of decay, and t = time)
Let's use what we know and fill in the expression.
[tex]0.08 = 0.20(1-0.47)^t[/tex]
And now we solve for t.
[tex]0.08 = 0.20(0.53)^t \\ 0.4 = 0.53^t \\ log0.4=t*log0.53 \\ t = \frac{log0.4}{log0.53} = \boxed{1.44\ hours}[/tex]
[tex]A = p(1-k)^t[/tex]
(where A = new amount, p = principal (starting) amount, k = rate of decay, and t = time)
Let's use what we know and fill in the expression.
[tex]0.08 = 0.20(1-0.47)^t[/tex]
And now we solve for t.
[tex]0.08 = 0.20(0.53)^t \\ 0.4 = 0.53^t \\ log0.4=t*log0.53 \\ t = \frac{log0.4}{log0.53} = \boxed{1.44\ hours}[/tex]
Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Get the answers you need at Westonci.ca. Stay informed with our latest expert advice.