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What is the area of an equilateral triangle with an apothem of 6cm

Sagot :

AyaZ
[tex]A= \frac{1}{2} bh \\ b=6 \\ h=b*sin60 \\ A= \frac{1}{2} *6*6*sin60=18* \frac{ \sqrt{3} }{2} =9 \sqrt{3} [/tex]
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