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A rectangular parking lot is enclosed by concrete barriers 5 feet long. There are 160 barriers in total. Determine the maximum area that can be enclosed.

Sagot :

Well you just multiply 5 by 160 and get 800ft

Maximum area  of rectangular park that can be enclosed using 5 feet long concrete barriers is equals to 40,000 square feet.

What is rectangle?

" Rectangle is defined as quadrilateral whose opposite sides are parallel and congruent with one of the angle equals to 90°."

According to the question,

Length of the concrete barrier = 5feet

Number of barriers = 160

Total length of barriers = 160 × 5

                                       = 800 feet

'l' represents the length of the rectangular park

'w'  represents the width of the rectangular park

'A' represents the area of the rectangular park

Perimeter of the Rectangular park = 2 ( length + width)

                                              ⇒800 = 2(l + w)

                                              ⇒ l + w = 400

                                              ⇒ w = 400 - l

Area of the rectangular park = length × width

                                              ⇒ A =  l  × ( 400 - l )

                                               ⇒A = 400l - l²

                                              ⇒[tex]\frac{dA }{dl} = 400 -2l[/tex]

                                              ⇒ [tex]\frac{d^{2} A}{dl^{2} }=-2 < 0[/tex]

Therefore , maximum function.

[tex]\frac{dA }{dl} =0[/tex]

⇒[tex]400 -2l =0[/tex]

⇒[tex]l= 200[/tex]

and

[tex]w = 200[/tex]

Maximum area that can be enclosed = 200 × 200

                                                              = 40,000 square feet.

Hence, maximum area  of rectangular park that can be enclosed using 5 feet long concrete barriers is equals to 40,000 square feet.

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