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Sagot :
[tex]2 \pi r=circumference of the circle
r=5.5
(5.5) x^{2} \pi =area
30.25 \pi =area[/tex]
30.25[tex] \pi [/tex] square inches is the area for the circle
30.25[tex] \pi [/tex] square inches is the area for the circle
C= pi d
therefore 11= diameter
radius is 1/2 the diameter
radius= 5.5
A= pi r^2
A=30.25 pi
hope this helps
therefore 11= diameter
radius is 1/2 the diameter
radius= 5.5
A= pi r^2
A=30.25 pi
hope this helps
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