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what are the solution of the equation x^2- 4x -32 = 0 ?show your work and justify each step.

Sagot :

x^2-4x-32=0

(x+a)(x+b)

x^2-(a+b)x+ab

a+b=4
ab=-32

a=-b+4
(-b+4)b=-32

-b^2+4b=-32
b^2-4b-32=0
b=8,-4

If b=8, a=-4
If b=-4, a= 8

Plug in a and b to (x+a)(x+b)
x= -4, 8