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Help?? Calculate the density of a bar of gold with a length of 10 cm, a width of 9 cm, a height of 6 cm, and a mass of 873 g. A.) 1.62 g/cm3 B.) 540 g/cm3 C.) 540 cm3

Sagot :

D = m/v
1) 10*9*6 = 540 cm3 (volume of bar)
2) 873/540 = 1.62 g/cm3

The answer is A)


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