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Sagot :
Alright in this one, you are going to need to factor.
The width is x
The length is 2x-4
To find the area of a rectangle is L*W
so (2x-4)(x) when distributed is 2x^2 -4x
Then put that in the equation and you have:
2x^2 -4x = 96
2x^2 -4x -96 = 0
2x^2+12x-16x-96=0
3x(x+4)-4(x+4)=0
(3x-4)=0
(x+4)=0
x=-4
x=3/4
Since length isn't negative
we will use 3/4 as x.
Width= 0.75 ft
Length= 1.5
The width is x
The length is 2x-4
To find the area of a rectangle is L*W
so (2x-4)(x) when distributed is 2x^2 -4x
Then put that in the equation and you have:
2x^2 -4x = 96
2x^2 -4x -96 = 0
2x^2+12x-16x-96=0
3x(x+4)-4(x+4)=0
(3x-4)=0
(x+4)=0
x=-4
x=3/4
Since length isn't negative
we will use 3/4 as x.
Width= 0.75 ft
Length= 1.5
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