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what is the mass of the block of iron illustrated below?

What Is The Mass Of The Block Of Iron Illustrated Below class=

Sagot :

PBCHEM

Answer : 787.4 g

Explanation : With the given information; the volume of the block will be equal to = 5 cm X 10 cm X 2 cm = 100 [tex] cm^{3} [/tex].

Therefore, the volume will be 100 [tex] cm^{3} [/tex].

but density of iron is found to be [tex] 7.874 g/cm^{3} [/tex]

So, now calculating for mass; on the basis of the density formula;

which is density = mass/volume; so, mass = density X volume;

Therefore, mass will be 7.874 g X 100 = 787.4 g

mass of the iron block = 787.4 g

Explanation:

Given that,

The dimensions of the block of iron is 2 cm, 10 cm and 5 cm

To find,

The mass of the block.

Solution,

We know that, the density of iron is, d = 7.874 g/cm³

Density, [tex]d=\dfrac{m}{V}[/tex]

Where

m is mass and V is volume

Solving for m,

[tex]m=d\times V[/tex]

The block is in the form of a cuboid, [tex]V=lbh[/tex]

So,

[tex]m=d\times l\times b\times h\\\\m=7.874 \times 2\times 10\times 5\\\\m=787.4\ g[/tex]

Answer,

The mass of the block of iron is [tex]787.4\ g[/tex].

Reference,

https://brainly.com/question/5189059

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