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Sagot :
x² - 6x - 27 = 0
x = -(-6) +/- √((-6)² - 4(1)(-27))
2(1)
x = 6 +/- √(36 + 108)
2
x = 6 +/- √(144)
2
x = 6 +/- 12
2
x = 3 + 6
x = 3 + 6 x = 3 - 6
x = 9 x = -3
x = -(-6) +/- √((-6)² - 4(1)(-27))
2(1)
x = 6 +/- √(36 + 108)
2
x = 6 +/- √(144)
2
x = 6 +/- 12
2
x = 3 + 6
x = 3 + 6 x = 3 - 6
x = 9 x = -3
The quadratic equation x² - 6x - 27 = 0 is equivalent to (x - 3)² = 36. Then the correct option is C.
What is a quadratic equation?
It's a polynomial with a value of zero. There exist polynomials of variable power 2, 1, and 0 terms. A quadratic equation is an equation with one statement in which the degree of the parameter is a maximum of 2.
The quadratic equation is given below.
x² - 6x - 27 = 0
The quadratic equation can be written as
Add 9 on both sides, then we have
x² - 6x + 9 = 9 + 27
(x - 3)² = 36
More about the quadratic equation link is given below.
https://brainly.com/question/2263981
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