Answered

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Find the midpoint of the line segment whose endpoints are (7, 5) and (7, 11).

(0, 6)
(7, 3)
(7, 8)

Sagot :

Nekoneko
[tex]( \frac{x_{1}+ x_{2} }{2} , \frac{y_{1}+ y_{2} }{2} ) ( \frac{7+ 7 }{2} , \frac{5+ 11 }{2}) ( \frac{14 }{2}, \frac{ 16 }{2}) (7, 8)[/tex]

Answer:

(7, 8)

Step-by-step explanation:

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