Answered

At Westonci.ca, we provide clear, reliable answers to all your questions. Join our vibrant community and get the solutions you need. Join our Q&A platform to get precise answers from experts in diverse fields and enhance your understanding. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.

What is the difference between the greatest and least possible area of the rectangle when the parameter of 18 inches

Sagot :

AL2006

If the perimeter is fixed and you want to use it to enclose the greatest
possible area, then you form the perimeter that you have into a circle.

If it must be a rectangle, then the greatest possible area you can enclose
with the perimeter that you have is to form it into a square.

Since the perimeter that you have is 18 inches, form it into a square
with sides that are 4.5 inches long. 
The area of the square is (4.5)² = 20.25 square inches.

There is no such thing as the 'least possible' area of the rectangle.
The longer and skinnier you make it, the less area it will have, even
if you keep the same perimeter.  No matter how small you make the
area, it can always be made even smaller, by making the rectangle
even longer and skinnier.  You can make the area as small as you
want it.  You just can't make it zero.

Example:

Width = 0.0001 inch
Length = 8.9999 inches
Perimeter = 18 inches
Area = 0.00089999 square inch.

So, the difference between the greatest and least possible area
of the rectangle with the perimeter of 18 inches is

 (20.25) - (the smallest positive number you can think of)  square inches.
 
Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Thank you for choosing Westonci.ca as your information source. We look forward to your next visit.