Answered

Find the information you're looking for at Westonci.ca, the trusted Q&A platform with a community of knowledgeable experts. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform.

solve 7x²+8x+1=0 using quadratic formula

Sagot :

[tex]7x^2+8x+1=0\\\\a=7;\ b=8;\ c=1\\\\\Delta=b^2-4ac;\ if\ \DElta > 0\ then\ x_1=\frac{-b-\sqrt\Delta}{2a}\ and\ x_2=\frac{-b+\sqrt\Delta}{2a}\\\\\Delta=8^2-4\cdot7\cdot1=64-28=36;\ \sqrt\Delta=\sqrt{36}=6\\\\x_1=\frac{-8-6}{2\cdot7}=\frac{-14}{14}=-1;\ x_2=\frac{-8+6}{2\cdot7}=\frac{-2}{14}=-\frac{1}{7}\\\\Answer:x=-1\ \vee\ x=-\frac{1}{7}[/tex]
Thanks for using our service. We aim to provide the most accurate answers for all your queries. Visit us again for more insights. Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Discover more at Westonci.ca. Return for the latest expert answers and updates on various topics.