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Sagot :
I think it would be no solution
4x-2(2x+8)=8
4x-4x+16=8
0x+16=8
16=8
which is wrong
4x-2(2x+8)=8
4x-4x+16=8
0x+16=8
16=8
which is wrong
[tex]\begin{cases} 4x-2y=8 \\ y=2x+8 \end{cases} \\ \\\begin{cases} 4x-2y=8 \\-2x+ y= 8 \ \ /*2\end{cases}\\ \\\begin{cases} 4x-2y=8 \\-4x+ 2y= 16 \ \ /*2\end{cases} \\+ \ \ -------- \\ 0=24 \\ \\ Answer : \ no \ solution[/tex]
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