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Sagot :
5.98E24 kg, and rounded I would not be able to determine, since it is a very large and complex equation.
The mass of the water on Earth in Kilograms with the given parameters is;
Mass = 97.335 × 10¹⁹ kg
We are given;
Average depth of water; h = 2.3 miles = 2701.49 m
Now, radius of earth is; r = 6400000 m
Also, density of water is; ρ = 1000 kg/m³
Since the earth is spherical, then surface Area is;
A = 4πr²
Thus; A = 4π × 6400000²
A = 16.384π × 10¹³ m²
Now, formula for volume is;
V = Ah
Thus; V = 16.384π × 10¹³ × 2701.49
V = 139.05 × 10¹⁶ m³
We are told the earth is 70% Water.
Thus, water volume = 0.7 × 139.05 × 10¹⁶
water volume = 97.335 × 10¹⁶ m³
Formula for mass from density and volume is;
mass = density × water volume
Thus;
mass = 1000 × 97.335 × 10¹⁶
Mass = 97.335 × 10¹⁹ kg
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